5[2(x+2)+5] what is the answer?

5[2(x+2)+5] = 0
5(2x+4+5) = 0
5(2x+9) = 0
2x+9 = 0
2x = -9
so x = -9/2 = -4.5

= 5(2[x + 2] + 5)
= 5(2x + 4 + 5)
= 5(2x + 9)
= 10x + 45

Answer: 10x + 45 or 5(2x + 9)

5 (2x + 9)
10 x + 45

5[2(x+2)+5]
= 5[2x+4+5]
= 5[2x+9]
= 10x+45

The answer is 10x+45

5[2(x + 2) + 5]
= 5[2*x + 2*2 + 5]
= 5[2x + 4 + 5]
= 5[2x + 9]
= 5*2x + 5*9
= 10x + 45

I'm not sure what "answer" you're looking for. You cannot solve this for a value of "x." All you can do is simplify it. If that's what you're trying to do, then this is how it is done:

5[2(x + 2) + 5]

= 5[2x + 4 + 5]

= 5[2x + 9]

= 10x + 45

That's all you can do with this.

5[2(x+2)+5]
=5[2x+4+5]
=5[2x+9]
=10x+45

5[(2x+4)+5]= 5(2x+9)= 10x+45

5[2(x+2)+5]
=5(2x+2+5)
=5(2x+7)
=10x+35

5 * [2(x + 2) + 5]
5 * (2x + 4 + 5)
5 * (2x + 9)
10x + 45

**If you have this set to 0
10x + 45 = 0
10x = -45
x = -4.5

5[2x+4+5] = 5( 2x+9)
= 10 x +45