上面好多個人都做錯數呀 題目話因式分解呀 唔係展開呀
(2x+1)(x-y)-(3x+1)(x-y)<--當中(x-y)係(2x+1)(x-y)&(3x+1)(x-y)都有既項
所以就要抽(x-y)出黎
如下
(2x+1)(x-y)-(3x+1)(x-y)
=(x-y)((2x+1)-(3x+1))
=(x-y)(2x+1-3x-1)
=(x-y)(-x)<--去左咁既樣呢,就要展開啦p.s(x-y)(單一個數)
=y-x
如果你仲係唔明既話,就將x-y當係a咁睇
設x-y為a
(2x+1)(x-y)-(3x+1)(x-y)
=(2x+1)a-(3x+1)a
=a((2x+1)-(3x+1))
=a(2x+1-3x-1)
=a(-x)<--而家先將(x-y)代返入去a都得,方便你計就得
仲係唔識就聯絡我啦
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