Can someone factor this? --8x^3 + 27 ( Eight X to the third + 27)?
回答 (3)
2008-09-21 4:44 pm
✔ 最佳答案
(2x)^3 + 3^3(2x + 3)^3
2008-09-21 11:48 pm
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
8x^3 + 27
= (2x)^3 + 3^3
= [2x + 3][(2x)^2 - 6x + 3^2]
= [2x + 3][4x^2 - 6x + 9]
8x^3 + 27
= (2x)^3 + 3^3
= [2x + 3][(2x)^2 - 6x + 3^2]
= [2x + 3][4x^2 - 6x + 9]
2008-09-22 12:16 am
8x^3 + 27 = (2x)^3 + 3^3 = (2x + 3)(4x^2 - 6x + 9)
x3 + y3 = (x+y)(x2-xy+y2)
x3 + y3 = (x+y)(x2-xy+y2)
收錄日期: 2021-05-01 11:17:09
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