simplify: 4x(x-3) + 2x(4x+3)?

4x^2-12x+8x^2+6x= distribute
12x^2-6x combine like terms

−3−(−3)(−3)−3(−3) = -3 - 9 + 9 = -3

4x(x - 3) + 2x(4x + 3)
= 4x*x - 4x*3 + 2x*4x + 2x*3
= 4x^2 - 12x + 8x^2 + 6x
= 4x^2 + 8x^2 - 12x + 6x
= 12x^2 - 6x
= 6(2x^2 - x)
= 6x(2x - 1)

4x² - 12x + 8x² + 6x
12x² - 6x

Your first step is to perform the indicated multiplications

4x(x - 3) + 2x(4x+3) =4x^2 - 12x + 8x^2 + 6x

Next collect and combine like terms which gives 12x^2 - 6x.

Then factor out 6x to give 6x(2x - 1).

4x(x-3) + 2x(4x+3)

4x^2 - 12x + 8x^2 + 6x

12x^2 - 6x

6x(2x-1)

4x(x - 3) + 2x(4x + 3)
4x^2 - 12x + 8x^2 + 6x
12x^2 - 6x
6x(2x - 1)