Math Help!QUICK PLEASE!?

2008-09-17 10:08 am
1.5x-3=y
2.2x+1=y

I don't need y but you can give it if you want
but what is x equal in each problem?

回答 (5)

2008-09-17 10:14 am
✔ 最佳答案
Currently the equations are solved for y. The question asks you to instead solve them for x. So you want to perform operations that will isolate x on one side.

PROBLEM 1:
5x - 3 = y

Add 3 to both sides:
5x - 3 + 3 = y + 3
5x = y + 3

Divide both sides by 5:
x = (y + 3) / 5

PROBLEM 2:
2x + 1 = y

Subtract 1 from both sides:
2x = y - 1

Divide both sides by 2:
x = (y - 1) / 2
2008-09-17 10:24 am
1)
5x - 3 = y
5x = y + 3
x = (y + 3)/5

2)
2x + 1 = y
2x = y - 1
x = (y - 1)/2
2008-09-17 10:19 am
y = y
5x-3 = 2x+1
3x = 4
x = 4/3
then
y = 5x-3 = 5[4/3]-3 = 20/3 - 9/3 = 11/3
then
[x,y] = [4/3,11/3]
2008-09-17 10:16 am
5x - 3 = y
5x = y + 3
x = (y + 3)/5

Answer: x = (y + 3)/5

2x + 1 = y
2x = y - 1
x = (y - 1)/2

Answer: x = (y - 1)/2
2008-09-17 10:16 am
5x - 3 = y --------------------------------(1)
2x + 1 = y ---------------------------------(2)

Subtract equation (1) from equation (2). We get
(5x - 3) - (2x + 1) = y - y
Or 5x - 3 - 2x - 1 = 0
Or 5x - 2x - 3 - 1 = 0
Or 3x - 4 = 0
Or 3x = 4
Or x = 4/3
Substitute this value of x in equation (1). We get
5 * 4/3 - 3 = y
Or 20/3 - 3 = y
Or 11/3 = y
Or y = 11/3

Ans: x = 4/3, y = 11/3


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