Solve 2x^2 - 3x=0......?

Factor:

x(2x - 3) = 0

Set each factor equal to 0 and solve separately.

x = 0

and

2x - 3 = 0
x = 3/2

2x 2 3x 0

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RE:
Solve 2x^2 - 3x=0......?

x (2x - 3) = 0
x = 0 , x = 3 / 2

2x^2 - 3x = 0
x(2x - 3) = 0

x = 0

2x - 3 = 0
2x = 3
x = 3/2 (1.5)

∴ x = 0 , 3/2 (1.5)

assume x not equal to zero and divide the equation by x to get
2x - 3 = 0
2x = 3
x = 3/2 = 1.5
or x=0

2x^2-3x=0
x(2x-3)=0
Thus x=0 or 2x-3=0 ( to mult. out to 0, at least 1 term must = 0)
and 2x=3,
x=3/2

Factor out the x to get x(2x-3)=0 From this we find that x=0 and x=3/2 will both make the equation equal to 0.

x = 3 / 2