solve this using quadratic formula?

2008-09-14 7:26 pm
^ = exponent 4x^2-13x+3=0

回答 (2)

2008-09-14 7:32 pm
✔ 最佳答案
4x^2 - 13x + 3 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 4
b = -13
c = 3

x = [13 ±√(169 - 48)]/8
x = [13 ±√121]/8
x = [13 ±11]/8

x = [13 + 11]/8
x = 24/8
x = 3

x = [13 - 11]/8
x = 2/8
x = 1/4 (0.25)

∴ x = 1/4 (0.25) , 3
2008-09-15 2:39 am
x = [ 13 ± √ (169 - 48 ) ] / 8
x = [ 13 ± √ (121) ] / 8
x = [ 13 ± 11 ] / 8
x = 24 / 8 , x = 2 / 8
x = 3 , x = 1/4


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