Form 3 maths 指數定律 10分!

2008-09-15 12:02 am
Simplify the following expressions.
1. -1/2.(-2/3)^3.(-3^2)^3

2. 9c^2.(-6c^-3)

3. 27^n+1/3^2n-1

4. 4^x.8^x+2/2^x+6.4^2x

回答 (2)

2008-09-15 2:06 am
✔ 最佳答案
1.
-1/2 *(-2/3)^3 *(-3^2)^3
= -1/2*(-2*9/3)^3 <------- a^3*b^3 =a*b*a*b*a*b=(ab)^3
= -1/2*6^3
= -108
====================================================
2.
9c^2.(-6c^-3)
= -54c^(2-3)
= -54/c <- c^-1= 1/c
====================================================
3.
27^(n+1)/3^(2n-1)
=3^3n *27 /3^2n *(1/3) <-- 嘗試將佢整到可以約走個n
=3^n *3^4
=3^(n+4)
=====================================================
4.
4^x *8^(x+2) / 2^(x+6) *4^2x
=2^2x *2^4x *64 / 2^x *2^4x *64 <--解題方向同3一樣
=2^x

2008-09-14 18:09:04 補充:
第4題睇錯-...= ='''
應該係
4.
4^x *8^(x+2) / 2^(x+6) *4^2x
=2^2x *2^3x *2^6 / 2^x *2^4x *2^6 <--解題方向同3一樣
=0
參考: 腦, .....
2008-09-15 12:49 am


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