(開方2 )x^2-5x+2(開方2)=0
x=?,? 請以根號表示！
一元二次方程題目(1條)
2008-09-14 3:01 am
回答 (2)
2008-09-14 3:29 am
x = {5 +/- sqrt[ 25 - (4)(sqrt2)(2sqrt2)]}/(2sqrt2)
= [5 +/- sqrt( 25 - 16)]/(2 sqrt2)
= [5 +/- 3]/(2sqrt 2)
= 4/sqrt 2 and 1/sqrt 2
= 2 sqrt 2 and (sqrt 2)/2
= [5 +/- sqrt( 25 - 16)]/(2 sqrt2)
= [5 +/- 3]/(2sqrt 2)
= 4/sqrt 2 and 1/sqrt 2
= 2 sqrt 2 and (sqrt 2)/2
收錄日期: 2021-04-25 23:23:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080913000051KK02003