指數及對數函數1條

[(log(x^2y^3)/(logx)]+(3/2)log(y)
=[(log(x^2y^3)/(logx)]+log(y^(3/2))
=[(log(x^2y^3)+(logx*log(y^(3/2))]/(log(x)
無法再化簡了。

我私自改一下題目
log(x^2y^3)/[(logx)+(3/2)log(y)]
=log(x^2y^3)/[(logx)+log(y^(3/2))]
=log(x^2y^3)/[(logx*(y^(3/2))]
=log(x^2y^3)/[(log(x^2y^3)^(1/2)]
=log(x^2y^3)/[(1/2)*(log(x^2y^3)]
=1/[(1/2)]
=2

不曉得對不對!不對請告知，以便刪除!

不懂請問!

化簡 log x^2y^3 / logx+3/2 logy
是不是有比較請楚

可以請版大把題目打清楚點嗎？　感謝～

2008-09-13 22:25:38 補充：
［(log x^2╳y^2)/( log x)］＋(3/2) log y ???

2008-09-13 22:43:53 補充：
上面有錯＝　＝

請問是這樣嗎？

［(log x^2╳y^３)/( log x)］＋(3/2) log y ???