ALGEBRA 2. PLEASE HELP ME VERIFY THIS! :)?

-[2z-(5z+2)=2+(2z+7)
=-(2z-5z-2=2+2z+7
=-2z+5z+2=2+2z+7
=-2z+5z-2z=2+7-2
=z=7

- (2z - [5z + 2]) = 2 + (2z + 7)
- (2z - 5z - 2) = 2 + 2z + 7
- (- 3z - 2) = 2z + 9
3z + 2 = 2z + 9
z = 7

Answer: z = 7. You're absolutely right!

Proof:
- (2[7] - [5{7} + 2]) = 2 + (2[7] + 7)
- (14 - [35] + 2) = 2 + (14 + 7)
- (12 - 35) = 2 + (21)
- (- 23) = 2 + 21
23 = 23

-[2z-(5z+2)=2+(2z+7)
-[2z-5z-2]=2+2z+7
-2z+5z+2=2+2z+7
3z+2=9+2z
3z-2z=9-2
z=7

I got the same answer :)

- [ 2z - 5z - 2 ] = 2z + 9
3z + 2 = 2z + 9
z = 7

Good luck in the exam---you appear to be on the right track.

-[2z - (5z + 2)] = 2 + (2z + 7)
-[2z - 5z - 2] = 2 + 2z + 7
-2z + 5z + 2 = 2z + 9
-2z - 2z + 5z = -2 + 9
z = 7

-[2z-(5z+2)]=2+(2z+7)

Ok, so simplify the innermost operations, that is, the quantities. Distribute the negative sign.

-[2z-5z-2]=2+2z+7

Combine like terms.

-[-3z-2]=2z+9

Distribute the negative sign onto the quantity.

3z+2=2z+9

Add -2 to the both sides of equation to isolate 3z.

3z+2-2=2z+9-2

Simplify.

3z=2z+7

Add -2z to the both sides of equation to isolate 7.

3z-2z=2z+7-2z

Simplify.

z=7

∴ z=7

You are correct.

-2z + 5z +2 = 2 +2z +7
or z = 7
Checks!

Your first step looks fine, but i'm not sure how you went from -(2z-5z-2)=2+2z+7 to 2z-5z-2z=2+7-2. You can see that it's not correct by plugging in your answer of z=7:

2z-5z-2z=2+7-2
2(7)-5(7)-2(7)=2+7-2
14-35-14=7
-35=7

Which is obviously untrue! So-- It's easiest to get rid of the negative sign on the outside of the parentheses first. You could multiply both sides by -1:

-(2z-5z-2) = 2+2z+7
2z-5z-2 = -2-2z-7

or you could add the part that's inside the parenteses to both sides:

-(2z-5z-2) = 2+2z+7
0 = 2+2z+7+2z-5z-2

Then combining all the z's on one side and the plan numbers on the other and simplifying will get you to your answer. You'll find that z is, indeed, equal to 7.

-{2z-(5z+2)}=2+(2z+7) multiply the negative through on the left side

-2z+(5z+2)=2+(2z+7) gather like terms on one side of the = sign

-2z+5z-2z=2+7-2 add or subtract like terms

-4z+5z=7

z=7

Looks good

there's a simple way to check: plug your answer back into the original equation! if you have the right answer you'll get something that makes sense, like 1=1 (that's what your answer MEANS; it's the number that makes the equation work). if you have the wrong answer you'll get something that DOESN'T make sense like 1=0.

everywhere you see 'z' write '7' instead, like this:

-[2*7 - (5*7+2)]=2+(2*7+7);
23=23

which is true, so you're fine.

always good to do a check like this, no matter how advanced you get. good luck on your exam!