Find the length of leg x on the right triangle. ?

68² = x² + 8²
x² = (68² – 8²)
= (68 + 8)(68 – 8)
= 76 × 60
= 4 × 19 × 4 × 15
x = 4√285 = 4 × 16.88 = 67.52 --- option d
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Use Pythagoras theorem:

x^2 + 8^2 = 68^2
x^2 + 64 = 4624
x^2 = 4560
x = √4560
x = 4√285

Option D is correct.

d. 4 x sqrt285 =67.52777206 = sqrt (68^2 - 8^2)

answer is d.

root (68^2 -8^2)
= root(4560)
=root(16x285)
=root(16) x root(285)
=4 root(285)

sqrt(68^2 -8^2)
sqrt(4624 -64)
sqrt(4560)

now you simplify the root.

sqrt(16*285)
4*sqrt(285)

d.
Does a rt triangle have "legs" or "sides"?