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a. x = 2sqrt30
b. x = 4sqrt293
c. x = 60
d. x = 4sqrt285
Find the length of leg x on the right triangle. ?
2008-09-12 1:22 pm
回答 (6)
2008-09-12 1:35 pm
✔ 最佳答案
68² = x² + 8²x² = (68² – 8²)
= (68 + 8)(68 – 8)
= 76 × 60
= 4 × 19 × 4 × 15
x = 4√285 = 4 × 16.88 = 67.52 --- option d
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2008-09-12 8:54 pm
Use Pythagoras theorem:
x^2 + 8^2 = 68^2
x^2 + 64 = 4624
x^2 = 4560
x = √4560
x = 4√285
Option D is correct.
x^2 + 8^2 = 68^2
x^2 + 64 = 4624
x^2 = 4560
x = √4560
x = 4√285
Option D is correct.
2008-09-12 8:32 pm
d. 4 x sqrt285 =67.52777206 = sqrt (68^2 - 8^2)
2008-09-12 8:28 pm
answer is d.
root (68^2 -8^2)
= root(4560)
=root(16x285)
=root(16) x root(285)
=4 root(285)
root (68^2 -8^2)
= root(4560)
=root(16x285)
=root(16) x root(285)
=4 root(285)
參考: me
2008-09-12 8:28 pm
sqrt(68^2 -8^2)
sqrt(4624 -64)
sqrt(4560)
now you simplify the root.
sqrt(16*285)
4*sqrt(285)
sqrt(4624 -64)
sqrt(4560)
now you simplify the root.
sqrt(16*285)
4*sqrt(285)
2008-09-12 8:26 pm
d.
Does a rt triangle have "legs" or "sides"?
Does a rt triangle have "legs" or "sides"?
收錄日期: 2021-05-03 14:24:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080912052211AA9omif