How do I solve 10/x = 25/15?

ok
you have to isolate x

10 = 25/15 x

then
x = 10/(25/15) = (10*15)/25 = 150/25 = 6

25 X 15

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If I understood your problem well, solution is: 3log2x+log5^2-log1/[25^(1/2)]=15 you use rule a*logb=logb^a 3log2x+log5^2-log5^ -1=15 this -1 can go before log, so - and -1 make + 3log2x+log5^2+log5=15 here you use rule loga+logb=log(a+b) 3log2x+log5^3=15 3(log2x+log5)=15 you can divide all by 3 log2x + log5=5 again loga+logb=log(a+b) log10x=5 now, you use fact that base here is 10, and again rule loga+logb=log(a+b) log10+ logx=5 rule log (base a) a is 1 1+logx=5 log(base 10)x=4 and now antilogarithmus: ask yourself a question: "which number I get when I power 10 by 4?" and the answer is x. so, final result is: x=10^4 understood?

10/x = 25/15
10/x = 5/3
x = 10/(5/3)
x = 10(3/5)
x = 30/5
x = 6

x / 10 = 15 / 25
x / 10 = 3 / 5
x = 30 / 5
x = 6

First think is to make x in the numenature (upstairs)
and that well be done by letting the two fractions (both sides) upsidedown
x / 10 = 15 / 25
OR
if you don't feel comfortable with this method you can multibly both sides with x and that well make
10 = 25x/15
Don't warry both ways are correct(for this problem only)
OK...let us continou with the first method
x / 10 = 15 / 25
multibly both sides with 10
x / 10 * 10 = 15 / 25 * 10
x = 150 / 25
x*1 = 150 / 25 / (5/5)
x = 150/5 / 25/5
x = 30 / 5
x = 6

25 / y = 10
15 / y = x

therefore y = 2.5
15 / 2.5 = 6

you need to cross multiply.

1. 10/x =25/15
2. (25)(x)=(10)(15)
3. 25x=150
4. divide 25 on both sides
5. answer is 6.

:)

Multiply both sides of the equation by x resulting in:
10=25x/15

Then multiply both sides by 15 resulting in:
10*15=25x or 150=25x

Then divide both sides by 25:
150/25=x or x=6 !!

10/x =25/15

= 10/x = 5/3

cross multiply

= 5x = 30

5x/5 = 30/5

x = 6

!!!