solving 5(x-3)=30+4x, x= ?

5 (x - 3) = 30 + 4x

5x - 15 = 30 + 4x

5x - 4x = 30 + 15

x = 45

5(x-3)=30+4x ---> given

5x -15 = 30 + 4x

5x -4x = 30 + 15

x = 45 --------> final answer

5x-15=30+4x
-4x
x-15=30
+15
x=45

Member because of the fact: November 11, 2007 finished factors: 2473 (point 3) * upload to My Contacts * Block consumer * perfect answer 13% * 624 solutions Member because of the fact: November 11, 2007 finished factors: 2473 (point 3) factors earned this week: a hundred and sixty * upload to My Contacts * Block consumer 2(2x - 3) = 30 - 5x the two on the outdoors is expanded to each little thing interior the (..) (2*2x) - (2*3) = 30 - 5x 4x - 6 = 30 - 5x something is particularly trouble-free only upload and subtract on the two ingredient of the equation till your left with x's on one ingredient and only numbers on the different 4x = 30 - 5x + 6 4x = 36 - 5x 4x + 5x = 36 9x = 36 x = 36/9 x = 4

5(x - 3) = 30 + 4x
5*x - 5*3 = 30 + 4x
5x - 15 = 30 + 4x
5x - 4x = 30 + 15
x = 45

First, use distributive property to get the value of 5(x-3). 5(x-3) is equal to 5x-15.

Second, get the additive inverse of 4x and -15. Then add them to similar terms. So 5x+(-4x)=5x-4x=x: and 30+15=45. Now the equation is x=45, and the value of x is 45.

5x - 15 = 30 + 4x
5x - 4x = 30 + 15
x = 45

5(x-3) = 30 +4x

multiply what's in the parenthesis

5x-15 = 30+ 4x

collect like terms

5x-4x-15+15 = 30+15 +4x-4x

x=45

x=45

x=45