1. [a^3-8b^3 / (2a-b)(a^2+4b^2+2ab)] *
[2a^2-3b^2+5ab / 2b-a]
2. {1/[1+(1/x)]}-{1/[x-(1/x)]}+(x+1/x-1)
F.3 Maths
2008-09-10 3:12 am
回答 (1)
2008-09-11 1:39 am
收錄日期: 2021-04-11 20:21:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080909000051KK01717