solve: x^4 + x^2 - 6 = 0?

(x^2 - 2)(x^2 + 3) = 0
x^2 = 2 or -3
x = +/-sqrt(2), +/-isqrt(3)

x^4 + x^2 - 6 = 0
x^4 + 3x^2 - 2x^2 - 6 = 0
(x^4 + 3x^2) - (2x^2 + 6) = 0
x^2(x^2 + 3) - 2(x^2 + 3) = 0
(x^2 + 3)(x^2 - 2) = 0

x^2 + 3 = 0
x^2 = -3
x = ±√-3 (imaginary number)

x^2 - 2 = 0
x^2 = 2
x = ±√2

∴ x = ±√2

x^4+x^2= -6

hmmm.....idk you cant take the sqrt of a negative.....interesting problem.....do the quadratic formula or factor im assuming...

( x ² + 3 ) ( x ² - 2 ) = 0
x ² = - 3 , x ² = 2
x ² = 3 i ² , x ² = 2
x = ± i √3 , x = ± √2

well you can easily simplify it to x^4 + x^2 = 6
and the you can just guess and check for x
i would do it for you but i'm too lazy...
=)

I THINK U R EQUATION IS WRONG .
NOT SATISFYING THE CONDITION = 0

x=1
right?
Im only 14