resolve in the partial fraction
8/x^4+4
我計到 x^4+4=(x^2-2x+2)(x^2+2x+2)
次後
8/x^4+4=a/x^2-2x+2 + b/x^2+2x+2
之後計唔到ans.
收錄日期: 2021-04-22 00:37:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080907000051KK01445