F.6 mathematical induction

2008-09-07 5:15 am
prove that for any positive integer n, there exist unique positive integers an
and bn such that
(1+√2)^2= an + bn√2
prove also that an is odd for all n

Actually, what I really want to know is how to solve the second question
"prove also that an is odd for all n"...
更新1:

I am sorry... It should be(1+√2)^n= an + bn√2

回答 (1)

2008-09-07 9:49 am
✔ 最佳答案
As follows:

圖片參考:http://hk.geocities.com/stevieg_1023/0odd22.gif


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