and bn such that
(1+√2)^2= an + bn√2
prove also that an is odd for all n
Actually, what I really want to know is how to solve the second question
"prove also that an is odd for all n"...
更新1:
I am sorry... It should be(1+√2)^n= an + bn√2
F.6 mathematical induction
2008-09-07 5:15 am
prove that for any positive integer n, there exist unique positive integers an
and bn such that
(1+√2)^2= an + bn√2
prove also that an is odd for all n
Actually, what I really want to know is how to solve the second question
"prove also that an is odd for all n"...
and bn such that
(1+√2)^2= an + bn√2
prove also that an is odd for all n
Actually, what I really want to know is how to solve the second question
"prove also that an is odd for all n"...
回答 (1)
2008-09-07 9:49 am
收錄日期: 2021-04-22 00:37:24
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https://hk.answers.yahoo.com/question/index?qid=20080906000051KK02738