Solve the equation
e.g.
X = .......
Thanks a lot
P.S.
Show the steps pls
更新1:
The ans is 1-k or k^2+K+1
更新2:
sorry it should be: 1-k or k^2+k+1
a maths problem
2008-09-07 5:13 am
(X-1)^2=k^2(x+k)
Solve the equation
e.g.
X = .......
Thanks a lot
P.S.
Show the steps pls
Solve the equation
e.g.
X = .......
Thanks a lot
P.S.
Show the steps pls
回答 (3)
2008-09-07 4:51 pm
✔ 最佳答案
(x – 1)2 = k2(x + k)x2 – 2x + 1 = k2x + k3
x2 – (2 + k2)x + (1 – k3) = 0
[x – (1 – k)][x – (1 + k + k2)] = 0
\ x = 1 – k 或 1 + k + k2//
2008-09-07 5:52 am
i don't understand...
x = [ (k + 2) √(k4 + 4k + 4k) ] / 2
x = { (k + 2) √[k (k + 4k + 4)] } / 2
x = [ (k + 2) √(k4 + 4k + 4k) ] / 2
x = { (k + 2) √[k (k + 4k + 4)] } / 2
2008-09-07 5:32 am
(x - 1) = k (x + k)
x - 2x + 1 = kx + k
x - (k + 2)x + (1 - k) = 0
x = [ (k + 2) √(k + 2) - 4(1 - k) ] / 2
x = { (k + 2) √[(k4 + 4k + 4) - 4 + 4k] } / 2
x = [ (k + 2) √(k4 + 4k + 4k) ] / 2
x = { (k + 2) √[k (k + 4k + 4)] } / 2
x = { (k + 2) √[k (k + 2)] } / 2
x = { (k + 2) √[k(k + 2)] } / 2
x = { (k + 2) [k(k + 2)] } / 2
x = [(k + 2) + k(k + 2)] / 2 or [(k + 2) - k(k + 2)] / 2
x = (k + 1)(k + 2) / 2 or (k - 1)(k + 2) / 2
希望幫到您！
x - 2x + 1 = kx + k
x - (k + 2)x + (1 - k) = 0
x = [ (k + 2) √(k + 2) - 4(1 - k) ] / 2
x = { (k + 2) √[(k4 + 4k + 4) - 4 + 4k] } / 2
x = [ (k + 2) √(k4 + 4k + 4k) ] / 2
x = { (k + 2) √[k (k + 4k + 4)] } / 2
x = { (k + 2) √[k (k + 2)] } / 2
x = { (k + 2) √[k(k + 2)] } / 2
x = { (k + 2) [k(k + 2)] } / 2
x = [(k + 2) + k(k + 2)] / 2 or [(k + 2) - k(k + 2)] / 2
x = (k + 1)(k + 2) / 2 or (k - 1)(k + 2) / 2
希望幫到您！
收錄日期: 2021-04-23 20:34:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080906000051KK02734