what does 2u(3u+4)+3u(2u+1) equal?

Multiply 2u with each term in the brackets.
Multiply 3u with each term in the brackets.
Then add the two answers.

2u (3u + 4) + 3u (2u + 1)
= 6u^2 + 8u + 6u^2 + 3u
= 12 u^2 + 11u

I hope that helps. :)

me07.

6 u ² + 8 u + 6 u ² + 3 u
12 u ² + 11 u

2u(3u + 4) + 3u(2u + 1)
= 2u*3u + 2u*4 + 3u*2u + 3u*1
= 6u^2 + 8u + 6u^2 + 3u
= 6u^2 + 6u^2 + 8u + 3u
= 12u^2 + 11u
= u(12u + 11)

2u(3u+4)+3u(2u+1) = ?

first distribute 2u to (3u+4) & 3u to (2u+1):
{ 3u(2u) + 4(2u) } + { 2u(3u) + 1(3u) } = ?

then multiply the necessary: (answer will be)
{6u^2 + 8u} + {6u^2 +3u} = ?

since the equation is addition, just remove the brackets:
6u^2 + 8u + 6u^2 +3u = ?

add the numbers with the same exponents of the coefficients: (i will just rewrite them in different way but the same equation for you to see)
6u^2 + 6u^2 + 8u +3u = ?

answer: 12u^2 + 11u

Ok then let's simplify...

Is this algebra? Then look at this

2u x (3u + 4) + (3u x (2u + 1) = ?
= (6u + 4) + (6u + 1)
= 12u + 5
It can't go further, because u and normal are different units.
The answer is then 12u + 5

Is it one of those things where you replace u with something else? Then let's pretend u=2

Simplified:
(2 x 2) x (3 x 2) + 4 + (3 x 2) x (2 x 2 + 1)
= 4 x 6 + 4 + 6 x 5
= 24 + 10 x 5
= 24 + 50
= 74

This answer will change depending on the value of u.

Hope I helped

2u(3u+4)+3u(2u+1) = (6u^2 + 8u) + (6u^2 + 3u) (distributive property)
= 6u^2 + 6u^2 + 8u+ 3u (commutative property)
= (6u^2 + 6u^2) + (8u+ 3u) (associative property)
=12u^2 +11u

distribute
for the first part, multiply 2u*3u and then 2u*4
(6u² + 8u) I'll let you get the next one