F.2 Maths 急教!!!

Steven

2008-09-06 5:18 am

請幫手factorize以下polynomial。( polynomial 中所有' 為 2次方, "為3次方)
1. (n+25)-(m+25)
2. -mn(ax+b)-m'n(ax+b)
3. (-a+b)(x-y)-(a+b)(x-y)
4. c(a+b)' - b(a+b)'
5. 5(3m-n)' - 5a(n-3m)
6. 5(x-y)" - 10(y-x)'
7. (c-d)' -5c+5d
8. (2b-c)(x'+2) + (c-2b)(2-x')
9. (4h-6k)' +3k-2h

回答 (1)

用戶7639

2008-09-06 7:29 pm

✔ 最佳答案

1. (n+25)-(m+25)
=n-m//

2. -mn(ax+b)-m2n(ax+b)
=mn(ax+b)(m-1)//

3. (-a+b)(x-y)-(a+b)(x-y)
=(x-y)[(-a+b)-(a+b)]
=-2a(x-y)//

4. c(a+b)2 - b(a+b)2
=(a+b)2(c-b)//

5. 5(3m-n)2 - 5a(n-3m)
=5(3m-n)2 +5a(3m-n)
=5(3m-n)[(3m-n)+a]
=5(3m-n)(a+3m-n)//

6. 5(x-y)3 - 10(y-x)2
=5(x-y)3 - 10(x-y)2
=5(x-y)2[(x-y)-2]
=5(x-y)2(x-y-2)//
7. (c-d)2 -5c+5d
=(c-d)2 -5(c-d)
=(c-d)[(c-d)-5]
=(c-d)(c-d-5)//

8. (2b-c)(x2+2) + (c-2b)(2-x2)
=(2b-c)(x2+2) - (2b-c)(2-x2)
=(2b-c)[(x2+2)-(2-x2)]
=2x2(2b-c)//
9. (4h-6k)2 +3k-2h
=[2(2h-3k)]2 +3k-2h
=4(2h-3k)2-(2h-3k)
=(2h-3k)[4(2h-3k)-1]
=(2h-3k)(8h-12k-1)//

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