A student uses an electric kettle to heat 0.5 kg of water at 20 degrees.
The water boils in 4 mins.
Estimate the output power of the kettle.
Given that the specific heat capacity of water is 4200 Jkg^ -1 K ^-1
ANS =706W
Please shoe me the steps and answer more detail.
from CE 03-22 MC
Physics (計數)
2008-09-05 3:27 am
回答 (1)
2008-09-05 4:30 am
✔ 最佳答案
Assume no heat loss to the surroundings: By using E = mcΔT and E = Pt,
Energy gained by the water = energy given out by the heater
( 0.5 )( 4200 )( 100 - 20 ) = P ( 4 )( 60 )
P = 700W
P.S. I have checked the answer of that year and it should be 700W but not 706W.
參考: My Phy Knowledge
收錄日期: 2021-04-23 21:22:11
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