How do you solve this algebra question: x/4 - x/8=?

x/4 - x/8 = 2x/8 - x/8 = x/8

another method

asume x/4 - x/8 = y
then you need to get y
multiply the equation by 8
8x/4 - 8x/8 = 8y

2x - x = 8y
x = 8y
y = x/8

GOOD LUCK

x/4 - x/8
= 2x/8 - x/8
= (2x - x)/8
= x/8

You only have half the equation there, but you can "simplify that side" by using a common denominator of 8, so it will be "2x/8 - x/8" which will be x/8

4^x=(2^x)^2 8^x=(2x)^3 Let 2^x=y, then the equation could be re-written as y+y^2=y^3 or y^3 - y^2 - y=0 y(y^2 - y - 1)= 0 y=o and y^2 - y - 1= 0 this is quadratic equation which can be solved to ge the values of y which gives y=[1+sqrt(5)]/2 or y=[1-sqrt(5)]/2 subtituting the values of y in the expression 2^x=y and get the value for x, which would give two value of x x={log(1+sqrt(5)/2}/log2 = 0.6942 or x={log(1-sqrt(5)/2}/log2 =

2x / 8 - x / 8 = x / 8

x/4 - x/8
= (x/4)(2/2) - x/8
= 2x/8 - x/8
= x/8

This can't be solved. You need a term on the other side of the = sign.

x/4 - x/8
= 2x/8- 1x/8
= 1x/8
=x/8

It is actually simple, we did that stuff last year.

P.S i am 12. :)

simple...
X/4- X/8 is the same as 1/4X - 1/8X
1/4 is practically the same as 2/8
therefore, 2/8X -1/8X =1/8X

It's the same as 1/4x - 1/8x
so answer is 1/8x OR x/8 is the same thing