Factorize the following expression,include step
1.16x^3-4x-48
maths question, quick!!!!!!!!!!!!!!!!
2008-09-03 5:03 am
回答 (2)
2008-09-03 5:33 am
✔ 最佳答案
16x^3-4x-48 = 4[4x^3 - x - 12]
= 4[4x^3 - 9x + 8x -12]
= 4{x(4x^2 - 9) + 8x - 12]
= 4{[(2x)^2 - 3^2]x + 4(2x - 3)}
= 4[x(2x+3)(2x-3) + 4(2x-3)]
= 4(2x-3)[2x^2 + 3x +4]
2008-09-03 5:33 am
16x^3 - 4x - 48
= 4(4x^3 - x - 12)
= 4(2x - 3)(2x^2 + 4 +3x)
= 4(4x^3 - x - 12)
= 4(2x - 3)(2x^2 + 4 +3x)
收錄日期: 2021-04-25 22:36:16
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