這條數學題誰會做？
108 sweets and 88 chocolates are to be shared among some children. lf each child gets the same number of sweets and chocolates,how many sweets and chocolates each child gets at least?
求救！！這條數學題誰會做？
2008-09-02 12:21 am
回答 (2)
2008-09-02 12:42 am
✔ 最佳答案
the number of sweets and chocolates each child gets at least=H.C.F. of 108 and 88
=4
2008-09-02 12:44 am
Obviously, this question wants you to find the H.C.F. of the two numbers (108 & 88).
After finding the H.C.F, the answer shouts be 4.
Then, we divide the two numbers (108 & 88) by 4. There comes the answer.
Number of chocolate: 22
Number of sweets: 27
After finding the H.C.F, the answer shouts be 4.
Then, we divide the two numbers (108 & 88) by 4. There comes the answer.
Number of chocolate: 22
Number of sweets: 27
收錄日期: 2021-04-13 16:03:01
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https://hk.answers.yahoo.com/question/index?qid=20080901000051KK01291