How can i solve 1/3 (2x - 3) + 2 = 5/6 (x+3) -11/12?

1/3 (2x - 3) + 2 = 5/6 (x+3) -11/12
take 12 as the common deneominator
[4(2x-3)+24=10(x+3)-11]/12
cancel the denominator since it is an equation
open the brackets
8x-12+24=10x+30-11
collect like terms
8x+12=10x+19
bring like terms on the same side
12-19=10x-8x
-7=2x
-7/2=x
you're done
enjoy the full marks

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8x - 12 + 24 = 10x + 30 - 11
- 7 = 2x
x = - 7 / 2

1/3(2x - 3) + 2 = 5/6(x + 3) - 11/12
12[(2x - 3)/3 + 2] = 12[5(x + 3)/6 - 11/12]
4(2x - 3) + 24 = 10(x + 3) - 11
4*2x - 4*3 + 24 = 10*x + 10*3 - 11
8x - 12 + 24 = 10x + 30 - 11
8x + 12 = 10x + 19
8x - 10x = -12 + 19
-2x = 7
x = 7/-2
x = -7/2 (-3.5)

(2x-3)/3 + 2 = (5x+15)/6 - 11/12

Group the ones with "X" together on one side.

(2x-3)/3 - (5x+15)/6 = -11/12 - 2

Make them have the same denominator

(4x-6-5x-15)/6 = -35/12

(-x - 21)/6 = -35/12

Cross multioply them. To get rid of denominators.

12(-x - 21) = -35(6)

-12x - 252 = -210

-12x = 42

x = -3.5

distribute 1/3 and 5/6 to their corresponding parentheses.
and then simplify.

fist u multiply all
2/3x - 1 + 2 = 5/6x + 5/2 - 11/12
2/3x +1 = 5/6x + 19/12

then move all xs on one side
2/3x - 5/6x = 19/12 - 1
-1/6 x = 7/12
x= - 7/2

hope i helped