How can i solve (4x + 3)/9 - (2x + 1)/2 = 1/6?

2008-08-31 9:26 am

回答 (9)

2008-08-31 11:44 am
✔ 最佳答案
(4x + 3)/9 - (2x + 1)/2 = 1/6
18[(4x + 3)/9 - (2x + 1)/2] = 18(1/6)
2(4x + 3) - 9(2x + 1) = 3
2*4x + 2*3 - 9*2x - 9*1 = 3
8x + 6 - 18x - 9 = 3
8x - 18x = 3 - 6 + 9
-10x = 6
x = 6/-10
x = -3/5 (-0.6)
2008-08-31 9:32 am
First multiply by the common multiple of the denominators (in this case 18):
2*(4x + 3) - 9*(2x+1) = 3

Then simplify:
8x + 6 - 18x - 9 = 3
-10x - 3 = 3
-10x = 6
x = -6/10
x = -3/5

Answer:
x = -3/5
2008-08-31 9:33 am
find lowest common denominator.
2(4x+3)/18 - 9(2x+1)/18 = 1/6
8x + 6 - 18x - 9 = 1/6*(18)
-10x - 3 = 3
x = -6/10
參考: shortened it up but hopefully, you can see what i did there.
2008-08-31 9:30 am
Hmm. Start by... Multiplying 4x+3 and 1/6 by 9, then multiply 2x+1 and whatever 1/6 x 9 comes out to be by 2. Combine like terms, then solve for x as normal?

I think the answer would be... x=2?
2016-10-22 4:03 pm
multiply the 1st equ'n by using -2 and upload it to the 2d equation to get -4x+-2y=-2 + 4x+3y =9 y=7 so the 4x term cancels out and you get, y=7 then placed y back into the two between the staggering 2 equ'ns 4x+3(7) =9 4x = 9-21 x= -12/4 = -3 your anwser is (-3,7)
2008-08-31 4:02 pm
8x + 6 - 18x - 9 = 3
- 6 = 10 x
x = - 3 / 5
2008-08-31 9:33 am
Get the common denominator by multiplying by 18
2(4x+3) - 9(2x+1) = 3
8x+6 - 18x-9=3
6-10x-9=3
6-10x=12
6=12x+10x
x = - 0.6
2008-08-31 9:33 am
x = -6/10
2008-08-31 9:33 am
(4x+3)/9 - (2x+1)/2 = 1/6

Multiply both side by 18

2(4x+3) - 9(2x+1) = 3

(8x + 6) - (18x + 9) = 3

-10x -3 = 3

-10x = 6

x - -6/10 = -3/5


收錄日期: 2021-05-01 22:49:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080831012637AAJ1eQ4

檢視 Wayback Machine 備份