How can i solve 4y/5 - 14/15 = y/3?

group terms

4y/5 -y/3=14/15

on the left, the fractions become:

12y/15-5y/15=14/15

7y/15=14/15

y=2

4y/5 - 14/15 = y/3

12y/15 - 14/15 = 5y/15 (making the denominator the same)

12y - 14 = 5y (multiply by 15)

7y - 14 = 0 (minus 5y)

y = 2

4y/5 - 14/15 = y/3
cancel each term by 15.. then you'll have..

12y - 14 = 5y

12y - 5y = 14

7y = 14

y = 2

12 y - 14 = 5y
7y = 14
y = 2

4y/5 - 14/15 = y/3
15(4y/5 - 14/15) = 15(y/3)
3(4y) - 1(14) = 5(y)
12y - 14 = 5y
12y - 5y = 14
7y = 14
y = 14/7
y = 2

Multiply both sides by the common denominator of 15. This gives you
(4y)3 - 14 = y*5
12y - 14 = 5y

This is much easier to solve. Subtract 5y from both sides. Add 14 to both sides. Divide both sides by 7.

4y/5 - y/3 = 12y/15 - 5y/15 = 7y/15

so you can write

7y/15-14/15=0 --> y=2

multiply (4y/5) by (3/3) which should make (12y/15)
then (y/3) by (5/5). you'll get (5y/15)
then multiply both sides by 15.
you'll get. 12y-14=5y
-5y and +14 to both sides
7y=14
y=2