{ ab+bc-2ac/+5-(-6)+a}-{ab/c}
更新1:
點解第一度上方 多左個-6架,我唔多明...
我的弟弟的暑期功課一問
回答 (2)
2008-09-01 7:15 am
✔ 最佳答案
[ ab+bc-2ac/+5-(-6)+a]-[ab/c] =[ (+3)(-3)+(-3)(-5)-2(+3)(-6)/(+5)-(-6)+(+3)]-[(+3)(-3)/(-5)]
=[ (-9)+(+15)+(+36)/(+5)+6+(+3) ] - (-9/-5)
=[ 6 + (36/5) +9 ] - 9/5
=102/5 or 20.4 or 20又5分之2
參考: Hope i can help you
2008-09-02 12:20 am
[ ab+bc-2ac/+5-(-6)+a]-[ab/c]
=[ (+3)(-3)+(-3)(-5)-2(+3)(-6)/(+5)-(-6)+(+3)]-[(+3)(-3)/(-5)]
=[ (-9)+(+15)+(+36)/(+5)+6+(+3) ] - (-9/-5)
=[ 6 + (36/5) +9 ] - 9/5
=102/5 or 20.4 or 20又5分之2
=[ (+3)(-3)+(-3)(-5)-2(+3)(-6)/(+5)-(-6)+(+3)]-[(+3)(-3)/(-5)]
=[ (-9)+(+15)+(+36)/(+5)+6+(+3) ] - (-9/-5)
=[ 6 + (36/5) +9 ] - 9/5
=102/5 or 20.4 or 20又5分之2
收錄日期: 2021-04-29 22:00:11
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