不等式(1+x)(1-|x|)>0的解集是？
不等式解集(20點)
2008-08-31 7:40 am
回答 (1)
2008-09-03 9:38 pm
✔ 最佳答案
Solve (1 + x)(1 - |x|) > 0.(1 + x)(1 - |x|) > 0
(1 + x > 0 and 1 - |x| > 0) or (1 + x < 0 and 1 - |x| < 0)
(x > - 1 and |x| < 1) or (x < - 1 and |x| > 1)
(x > - 1 and - 1 < x < 1) or (x < - 1 and (x > 1 or x < - 1))
- 1 < x < 1 or x < - 1
參考: my maths knowledge
收錄日期: 2021-04-19 01:48:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080830000051KK03132