(3x^-3 * y^4 ) / (-x^2 * y^-6)
nothing to solve, just need to simplify
How do I simplify the below?
2008-08-28 3:59 pm
回答 (4)
2008-08-28 4:06 pm
✔ 最佳答案
Dividing like bases is a subraction of exponents so:(3x^-3 * y^4 ) / (-x^2 * y^-6)
-3x^(-3 - 2) * y^(4 - (-6))
-3x^(-5) * y^10
Removing the negative exponent:
-3y^10 / x^5
2008-08-28 11:29 pm
(3x^-3y^4)/(-x^2y^-6)
= (3/-1)(x^-3/x^2)(y^4/y^-6)
= -3[x^(-3 - 2)][y^(4 + 6)]
= -3[x^-5][y^10]
= -3[y^10/x^5]
= -3y^10/x^5
= (3/-1)(x^-3/x^2)(y^4/y^-6)
= -3[x^(-3 - 2)][y^(4 + 6)]
= -3[x^-5][y^10]
= -3[y^10/x^5]
= -3y^10/x^5
2008-08-28 11:09 pm
x^-3=(1/x^3)
y^-6=(1/y^6) or (1/y^-6)= y^6
now the expression
3 x^-3*y^4/(-x^2)*y^-6
=(-)[ 3 *(1/x^3)*y^4]/[x^2*(1/y^6]
=(-3)*y^10/x^5 ans
2008-08-28 11:04 pm
=3*(-1)*x^(-3-2)*y^(4-(-6))=
-3x^-5*y^2
-3x^-5*y^2
收錄日期: 2021-05-01 11:00:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080828075929AAJyiqW