6x-(5x-1)=2 what is the solution. show me how to work the problem?
回答 (13)
2008-08-28 1:32 pm
✔ 最佳答案
ok first ul have to distribute the - to eliminate the ( )6x - 5x + 1 = 2 --> to make it simple its like multiplying -1 to (5x-1)
then transfer your +1 to the other side of the equal sign
6x - 5x = 2 - 1 --> since you moved the 1 it gets a - and vice versa
do the subtraction
6x - 5x = 2 - 1 ---> x = 1 and thats your answer ^__^
since 6x and 5x are both the same (they both have 1 x) you can subtract it directly. so 6-5 = 1 because of the x you jsut add the x to the 1 which is x. its redundant to go 1x. simple subtraction for the other side 2-1 = 1.
now to further explain why the +1 becomes a -1 when you move it to the other side of the =, just think of it as a mirror, if you move anything across the = it gets its mirror image. so a +1 moved to the left becomes and -1 and a -1 move to the right of the = sign is a +1. hope this helps ^_^
參考: lots and lots and lots of math classes..im a computer science major...theres so much math i have nightmares about numbers sometimes
2008-08-28 11:50 pm
6x - (5x - 1) = 2
6x - 5x + 1 = 2
6x - 5x = 2 - 1
x = 1
6x - 5x + 1 = 2
6x - 5x = 2 - 1
x = 1
2008-08-28 8:58 pm
So easy.
6x-(5x-1)=2
6x-5x+1=2
x=1
6x-(5x-1)=2
6x-5x+1=2
x=1
2008-08-28 8:36 pm
6x minus (5x-1) = 2
First we have to get rid of the parenthesis. In order to do so, we have to multiply everything inside the parenthesis by one. And to do that, we have to change the equation so instead of 6x - (5x-1) = 2, It gets turned to 6x + -(5x-1) = 2, since subtraction is just another name for adding the opposite.
6x + -(5x-1) = 2
Even though it's not written, a one is implied in front of the parenthesis. So we'll multiply everything in the parenthesis by negative one.
6x + -5x + 1 = 2
-1 time 5x is -5x (pos times neg = neg)
-1 times -1 is a positive one (neg. times neg. = pos)
Combine like terms - add 6x + -5x to get 1x, or just x.
x + 1 = 2
Subtract the one from both sides to get x by inself, thus finding the answer!
x = 1
TADA~~~
I love problems like this, so if you need any more guidance let me know.
First we have to get rid of the parenthesis. In order to do so, we have to multiply everything inside the parenthesis by one. And to do that, we have to change the equation so instead of 6x - (5x-1) = 2, It gets turned to 6x + -(5x-1) = 2, since subtraction is just another name for adding the opposite.
6x + -(5x-1) = 2
Even though it's not written, a one is implied in front of the parenthesis. So we'll multiply everything in the parenthesis by negative one.
6x + -5x + 1 = 2
-1 time 5x is -5x (pos times neg = neg)
-1 times -1 is a positive one (neg. times neg. = pos)
Combine like terms - add 6x + -5x to get 1x, or just x.
x + 1 = 2
Subtract the one from both sides to get x by inself, thus finding the answer!
x = 1
TADA~~~
I love problems like this, so if you need any more guidance let me know.
2008-08-28 8:33 pm
6x-(5x-1)=2
6x-5x+1=2
x+1=2
x=1
6x-5x+1=2
x+1=2
x=1
2008-08-28 8:29 pm
Then 6x - 5x +1 = 2,x+1-2=0,x=1
2008-08-28 8:28 pm
6x-5x+1=2
therefore x=1
therefore x=1
2008-08-28 8:28 pm
6x + (1-5x) = 2 multiply minus sign through parenthesis
6x - 5x + 1 = 2 take away the parenthesis and put in order
x + 1 = 2 simplify the equation
x = 1 get 1 on a side by itself
6x - 5x + 1 = 2 take away the parenthesis and put in order
x + 1 = 2 simplify the equation
x = 1 get 1 on a side by itself
2008-08-28 8:24 pm
6x - 5x + 1 = 2
Take 1 to the other side:
6x - 5x = 1
Therefore, x = 1.
Take 1 to the other side:
6x - 5x = 1
Therefore, x = 1.
2008-08-28 8:23 pm
6x - 5x + 1 = 2 (remember to apply the neagtive to both terms in the bracket and that negative multiplied by a negative makes a positive.
x + 1 = 2
x = 1
x + 1 = 2
x = 1
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