幫幫手.....代數-求通項公式,thx~~

2008-08-29 4:41 am
1. 2,4,6,8,.... An=

2. 1/5,1/10,1/15,1/20,..... An=

3.-1/2,-1/4,-1/8,-1/16,.... An =

4.1-1/2,1/2-1/3,1/3-1/4,1/4-1/5,.... An=

回答 (2)

2008-08-29 5:31 am
✔ 最佳答案

1. 2,4,6,8,.... An = 2n

2. 1/5,1/10,1/15,1/20,..... An = 1/(5n)

3.-1/2,-1/4,-1/8,-1/16,.... An = -1/(2n)

4.1-1/2,1/2-1/3,1/3-1/4,1/4-1/5,.... An = 1/n - 1/(n+1)
=
2008-08-29 5:28 am
求緊個gerneral term?
1. 2n (while n = nth term)
2. 1/5n
3. -(1/2n)
4. 1/n-(n/n+1)


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