if y equals 7 and z equals 6, whats the value of 4y + 2z ?

Your question, 4y+2z = 4x7+2x6.
So, 28+12=40
The value is 40.

in case you upload the 1st 2 equations, you will get rid of z, and get an equation basically related to x and y. in case you upload 4 circumstances the 1st equation to the third, you will elimnate z, and get yet another equation related to basically x and y. From there, you basically have 2 equations with basically x and y, and can sparkling up as you probably did in the past. The trick is to systematically get rid of one variable at a time. that's not significant which. you ought to get rid of x first, or y first in case you want. in a while, they might instruct you ordinary suggestions on a thank you to place the coefficients right into a matrix and use Cramer's rule to sparkling up for x, y, and z. you could look that up on Wikipedia if that's what you're reading now.

28 + 12 = 40

y = 7
z = 6

4y + 2z
= 4(7) + 2(6)
= 28 + 12
= 40

y=7 z=6
4y+2z= 4(7)+2(6)=28+12=40

40

4(7) + 2(6)
28 + 12
=
40

40

40

40