Please reduce 3√a^6*9 / 3a^2 ?

2008-08-27 5:50 pm
The square root is just for the numbers before the division sign.

回答 (5)

2008-08-27 5:55 pm
✔ 最佳答案
3√(a^6*9) / 3a^2

3a^3*3 / 3a^2
3a

.
2008-08-28 1:41 am
Presentation leaves a lot to be desired.
Will take a GUESS at :-

[ 3 √ ( a^6 (9) ) ] / ( 3 a ²)

[ 9 a³ ] / ( 3 a ²)

3 a

2008-08-28 12:58 am
3√(a^6*9) / 3a^2 =
3√(a^3*a^3*3*3) / 3a^2 =
3(a^3)(3) / 3a^2
3a
2008-08-28 12:55 am
3√(a^6 * 9) / 3a^2

3√((3a^3)^2) / 3a^2

3*3*a^3 / 3a^2

3*(3*a^2)*a / 3a^2

3a
2008-08-28 12:56 am
3√(a^9 * 9)/3a^2 (cancel out 3)
= √(9a^6)/3a^2
= √(3a^3 * 3a^3)3a^2
= 3a^3/3a^2
= (3/3)(a^3/a^2)
= a^(3 - 2)
= a


收錄日期: 2021-05-01 11:05:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080827095044AAYSeua

檢視 Wayback Machine 備份