checking my answer(-1/125)^-4/3?
回答 (6)
2008-08-27 11:41 am
✔ 最佳答案
This is debatable. From a real number point of view, you can't take a non integral power of a negative number. 
2008-08-27 6:50 pm
See! You can do it yourself (now).
2008-08-27 6:47 pm
CORRECT!! nice work
firstly ³â[1/(-1/125)⁴]
then, ³â[1/(1/125⁴)]
then, ³â[1/(1/5⁴ x 1/5⁴ x 1/5⁴)]
then, 1/(1/5⁴)
then, 1(5⁴/1)
finally, 5⁴
therefore, it = 625
firstly ³â[1/(-1/125)⁴]
then, ³â[1/(1/125⁴)]
then, ³â[1/(1/5⁴ x 1/5⁴ x 1/5⁴)]
then, 1/(1/5⁴)
then, 1(5⁴/1)
finally, 5⁴
therefore, it = 625
2008-08-27 6:41 pm
(-1/125)^(-4/3)
= ³â[1/(-1/125)⁴]
= ³â[1/(1/125⁴)]
= ³â[1/(1/5⁴ x 1/5⁴ x 1/5⁴)]
= 1/(1/5⁴)
= 1(5⁴/1)
= 5⁴
= 625
= ³â[1/(-1/125)⁴]
= ³â[1/(1/125⁴)]
= ³â[1/(1/5⁴ x 1/5⁴ x 1/5⁴)]
= 1/(1/5⁴)
= 1(5⁴/1)
= 5⁴
= 625
2008-08-27 6:40 pm
Well, firstly 1/125 is 5^(-3)
So [(-5)^(-3)](^-4/3)
= (-5)^4
= 625
Yeah I got the same answer =)
So [(-5)^(-3)](^-4/3)
= (-5)^4
= 625
Yeah I got the same answer =)
收錄日期: 2021-05-01 11:06:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080827033600AAAVG8R