redox reaction..chem勁人入黎幫plx

The redox reaction is feasible when the O.A. (Oxidizing agents) reacts with R.A. (Reducing agents).

For example, the oxidation no. of potassium ion change from 1 to 0
i.e. K (O.N. = 1) e- -> K (O.N. = 0)

Potassium ions shows a decrease in oxidation number and that rectant is called Oxidizing agent.

Similarly, the oxidation no. of chlorine water change from 0 to -1
i.e. Cl 2 (O.N. = 0) 2e- -> 2 Cl- (O.N. = -1)

Chlorine water exhibits decrease in oxidation number and that reactant is called Oxidizing agent.

Thus, the redox reaction is not feasible because two oxidizing agents can't react with each other.

Finally, the oxidation number of iodide ion change from -1 to 0
i.e. 2I- (O.N. = -1) -> I2 (O.N. = 0) + 2e-

Iodide ion shows an increase in oxidation number and that reactant called Reducing agents.

The redox recations will take place if one O.A. (chlorine water) reacts with R.A. (Iodide ion). However, you may ask why iodide ion (R.A.) can't react with potassium.(O.A.) The reason is when the strongest O.A. (i.e. chlorine water) always reacts with the weakest R.A. (i.e. iodide ion), the greater chance of redox reaction will be occured instead.