y^2-6y+9 /////// y^2-9
________ //divide /// ________
-(y^2-4) /////// y^2-8y+12
Math help please? Not sure I am getting this. ?
2008-08-26 10:17 am
回答 (3)
2008-08-26 12:08 pm
✔ 最佳答案
(y^2 - 6y + 9)/-(y^2 - 4) ÷ (y^2 - 9)/(y^2 - 8y + 12)= (y^2 - 3y - 3y + 9)/-(y^2 + 2y - 2y - 4) * (y^2 - 2y - 6y + 12)/(y^2 + 3y - 3y - 9)
= (y - 3)(y - 3)/-(y + 2)(y - 2) * (y - 2)(y - 6)/(y + 3)(y - 3) (cancel out y - 3 , y - 2)
= (y - 3)/-(y + 2) * (y - 6)/(y + 3)
= (y - 3)(y - 6)/-(y + 2)(y + 3)
2008-08-26 10:43 am
your question is not clear
Factorise all terms
and get the answer
for eg factor of y^2-6y+9 = (y - 3)(y - 3)
y^2 - 9 = (y-3)3(y+3)
y^2 -4 = (y+2)(y-2)
y^2 - 8y +12 = (y-2)(y-6)
Factorise all terms
and get the answer
for eg factor of y^2-6y+9 = (y - 3)(y - 3)
y^2 - 9 = (y-3)3(y+3)
y^2 -4 = (y+2)(y-2)
y^2 - 8y +12 = (y-2)(y-6)
2008-08-26 10:39 am
I cannot understand. there is a lot of decoration there. The main problem cannot be understood! Well use the following if you can!
y^-6y+9 = (y-3)^2
y^2 -9= (y-3)(y+3)
y^2 - 4 = (y-2)(y+2),
y^ - 8y +12 = (y-6)(y-2)
(a/b)/(c/d) = ad/bc.
y^-6y+9 = (y-3)^2
y^2 -9= (y-3)(y+3)
y^2 - 4 = (y-2)(y+2),
y^ - 8y +12 = (y-6)(y-2)
(a/b)/(c/d) = ad/bc.
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