Maths question (Factorization)

👨🏻‍🏫 學術台數學

[匿名]

2008-08-27 3:47 am

There are a few questions ,I don't know how to factorize them.
Please answer me with steps and explain ,Thank you very much!

1) 2(3a-4b)^2-(4b-3a)
2)p^2+qr-q^2-pr
3)x^2-14x-72
4)2x^2-22x+48

Thank you again!

更新1:

唔好意思我想問多一條 5)6x^3-48y^3

回答 (1)

Uncle Michael

2008-08-27 4:11 am

✔ 最佳答案

1)
2(3a-4b)2-(4b-3a)
= 2(3a-4b)2+(3a-4b)
= (3a-4b)[2(3a-4b)+1]
= (3a-4b)(6a-8b+1)

=====
2)
p2+qr-q2-pr
= p2-q2-pr+qr
= (p2-q2)-(pr-qr)
= (p+q)(p-q)-r(p-q)
= [(p+q)-r](p-q)
= (p+q-r)(p-q)

=====
3)
x2-14x-72
= (x-18)(x+4)

=====
4)
2x2-22x+48
= 2(x2-11x+24)
= 2(x-3)(x-8)

=====
5)
6x3-48y3
= 6(x3-8y3)
= 6[x3-(2y)3]
= 6(x-2y)[x2+x(2y)+(2y)2]
= 6(x-2y)(x2+2xy+4y2)
=

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收錄日期: 2021-04-23 23:06:32
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