5x(x-3)(x-4)-2x2次方(x-3)
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數學難題!!!!!!!!!!5x(x-3)(x-4)-2x2次方(x-3)
2008-08-26 7:34 pm
回答 (3)
2008-08-26 7:51 pm
✔ 最佳答案
5x(x-3)(x-4) - 2x^2(x-3)= (x-3)[5x(x-4) - 2x^2]
= (x-3)(5x^2 - 20x - 2x^2)
= (x-3)(3x^2 - 20x)
= x(x-3)(3x - 20)
2008-08-26 7:46 pm
5x(x-3)(x-4)-2x2次方(x-3)
= 5 x ( x - 3 ) ( x - 4 ) - 2 x^2 ( x - 3 )
= 5 x ( x^2 - 4 x - 3 x + 7 ) - 2 x^3 + 6 x^2
= 5 x^3 - 20 x^2 - 15 x^2 + 35 x - 2 x^3 + 6 x^2
= 3 x^3 - 29 x^2 + 35 x
= 5 x ( x - 3 ) ( x - 4 ) - 2 x^2 ( x - 3 )
= 5 x ( x^2 - 4 x - 3 x + 7 ) - 2 x^3 + 6 x^2
= 5 x^3 - 20 x^2 - 15 x^2 + 35 x - 2 x^3 + 6 x^2
= 3 x^3 - 29 x^2 + 35 x
參考: ME
2008-08-26 7:44 pm
5x(x-3)(x-4)-2x2次方(x-3)
=(x-3)5x(x-4)-(x-3)2x*x
=(x-3)(5x*x-20x-2x*x)
=(x-3)(3x*x-20x)
=(x-3)5x(x-4)-(x-3)2x*x
=(x-3)(5x*x-20x-2x*x)
=(x-3)(3x*x-20x)
參考: myself
收錄日期: 2021-04-25 22:37:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080826000051KK00863