Amaths quadratic equations

2008-08-24 10:05 pm
If k is a real number, prove that the equation 4x^2+kx-3=0 has two unequal real roots and are of opposite signs.

Thanks!

回答 (2)

2008-08-24 10:15 pm
✔ 最佳答案
Equation 4x2 + kx - 3 = 0
Discriminant= k2 - 4(4)(-3)

= k2 + 48

> 0 (for k is a real number)

So, the equation 4x2 + kx - 3 = 0 has two unequal real roots.


Consider product of roots = -3/4

Since the product of roots are negative.

That implies one root must be positive and another root must be negative.

Therefore, the two unequal real roots are of opposite signs.

參考: Myself~~~
2008-08-24 10:20 pm
product of root=-3/4,
∆=(-k)2-4(4)(-3)
=k2+48
∴the equation has two unequal real roots and are of opposite signs.


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