x2+6x-1= (x+p)2+q
求 p及 q 的值
數學一題(請幫忙)
2008-08-24 11:28 am
回答 (1)
2008-08-24 11:46 am
✔ 最佳答案
x^2 + 6x - 1 = (x+p)^2 + qx^2 + 6x - 1 = x^2 + 2px + p^2 + q
so, 2p = 6
p = 3
and -1 = p^2 + q = 3^2 + q = 9 + q
q = -1 -9 = -10
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收錄日期: 2021-04-15 17:46:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080824000051KK00404