F.1 MATHS[急!!!!]thx!!!!!(20points)

2008-08-23 5:12 pm
1. Solve the equation 3(x-5) = 2x+7

2.Determine the number of axes of symmetry in the following figure:

圖片參考:http://xs330.xs.to/xs330/08345/__26410___21629___21517_651.png.xs.jpg


3.Consider polynomial 3x3-7x2-x+3 . Find the coefficients of x2 and the constant term.
Answer:Coefficients of x2:
Constant term:

4.State whether the given pair of triangles are congruent or not. Give the abbreviated reason.

圖片參考:http://xs330.xs.to/xs330/08345/__26410___21629___21517_112.png

5.Write q*q/s in the simplest form.

6.

圖片參考:http://xs330.xs.to/xs330/08345/__26410___21629___21517_106.png

the above figure has rotational symmetry.The order of rotational symmetry is_____________.

7.State whether △ABC and △PQR are congruent or simillar triangles,and give reason.

圖片參考:http://xs330.xs.to/xs330/08345/__26410___21629___21517_486.png


8.Express 12℅ as a fraction and a decimal.

回答 (2)

2008-08-23 6:02 pm
✔ 最佳答案
1. 3(x-5) = 2x+7
3x-15 = 2x+7
x = 22
2. 5
3.3x3-7x2-x+3
Coefficients of x2: -7
Constant term: +3
4.yes (SAS)
5. q2 / s
6. 8
7.simillar triangles ( 2條成比例且夾角相同)
8. 12% = 3/25(fraction)= 0.12(decimal)

請發問者自律不要移除問題
另請其他人不要抄襲或略作修改

2008-08-23 10:14:40 補充:
對不起002..你做錯了
4,6,7

第4可以係RHS
但是中一的同學未學pyth thm
唔識得求斜邊
而本身SAS已是原因了

6方面明顥是8

7我也錯了..應該是congruent (SAS)
而不是002的ASA

2008-08-23 10:17:02 補充:
第6係問The order of rotational
唔係問有幾多對稱軸
參考: me, 002, 補充
2008-08-23 6:06 pm
(1) 3(x-5) = 2x+7 >> 3x - 15 = 2x + 7 >> x = 7+15 =22
(2) 5 nos
(3) Coefficients of x2: -7
Constant term: 3
(4) AB= PQ, CB= QR, Angle ABC = Angle PQR = 90 degree
Triangle ABC = Triangle PQR (RHS)
(5) q^2/s
(6) 4
(7) AB = PQ = 6, BC = QR =5, Angle ABC = Angel PQR
They are congruent (ASA)
(8) 12% = 12/100 = 6/50 = 3/25
12% = 12/100 = 0.12


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