Simplify (8a^3b^2)(2a^-4b^-5)?
回答 (3)
2008-08-20 4:23 pm
(8a^3b^2)(2a^-4b^-5)
= (8)(2)(a^3)(a^-4)(b^2)(b^-5)
= [16][a^(3 - 4)][b^(2 - 5)]
= [16][a^-1][b^-3]
= [16][1/a][1/b^3]
= 16/ab^3
= (8)(2)(a^3)(a^-4)(b^2)(b^-5)
= [16][a^(3 - 4)][b^(2 - 5)]
= [16][a^-1][b^-3]
= [16][1/a][1/b^3]
= 16/ab^3
2008-08-20 4:12 pm
16 ( a^3 ) ( b² ) ( a^-4 ) ( b^-5 )
16 a^(-1) b^(- 3)
16 / ( a b ³ )
16 a^(-1) b^(- 3)
16 / ( a b ³ )
收錄日期: 2021-05-01 10:58:54
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