Algebra math question?

*Let:
x = cost of basketball
y = cost of football;

*since a football costs 15 $ more, you have the first equation:
y = x + 15 $

*next, if you bought 3 basketballs, and 2 footballs which costs 115 $, you will have the second equation: 115 $ = 3x + 2y

*substitute the first equation to the second:
115 $ = 3x + 2(x + 15 $)
115 $ = 3x + 2x + 30$
(put together similar terms and simplify, note the change of signs once you move an expression to the other side)
115 $ - 30 $ = 3x + 2x
85 $ = 5x
(divide both sides by 5 to get the value of x)
85$/5 = 5x/5
17$=x
so, a basketball costs 17$.

*to get the value of y/ or cost of football, substitute value of x to first equation.
y = x + 15 $
y = (17$) + 15 $
y = 32 $
so, a football costs 32$.

*to check the answer, substitute both values to second equation.
115 $ = 3x + 2y
115 $ = 3(17$) + 2(32$)
115 $ = 51$+ 64$
115 $ = 115 $
that means the answer is right.

~ hope this helps.

Let $ x = cost of basketball
=> $ x + 15 = cost of football
=> 3x + 2(x + 15) = 115
=> 5x = $ 85
=> x = $ 17
=> basketball costs $ 17 and football costs $ 32

x = football (solve by using substitution)
y = basketball

x = y + 15
3x + 2y = 115

3x + 2y = 115
3(y + 15) + 2y = 115
3y + 45 + 2y = 115
3y + 2y = 115 - 45
5y = 70
y = 70/5
y = 14

x = y + 15
x = 14 + 15
x = 29

∴ x (football) = 29 , y (basketball) = 14

Football = x + 15
Basketball = x

Total = (x) + (x + 15), So.....
3 Basketballs = 3,(x)
2 Footballs = 2(x + 15)
Total for all = 115

Final Equation is....
1.) 115 = 3(x) + 2(x+15)
2.) 115 = 3x + 2x + 30
3.) 115 = 5x + 30
4.) 115 -30 = 5x + 30 - 30 ----- 85 = 5x
5.) 85/5 = 5x/5
6.) 17 = x

Plug answer into X to find out price of each ball....

Basketball = x ---- therefore, basketballs are $17
Football = x + 15 ---- therefore, 17 + 15 = 32... footballs are $32

Basketballs = $17
Footballs = $32

To check your work:
3 * 17 = $51, 2(17 + 15) =$64, $51 + $64 = $115

F = 15 + B
3B+2F = 115

Plug F into the 2nd equation and solve for B

3B + 2(15 + B) = 115

3B + 30 + 2B = 115

3B + 2B = 85

5B = 85

B = $17

plug B back into equation

F = 15 + 17 = 32

Than check answer by putting back into equation

3B+2F = 3(17) + 2(32) = 51 + 64 = 115 which checks

Make the equation first

basketball= x
football= (x+15)

3x + 2(x+15) =115
5x + 30 = 115
5x = 85
x = 85/5
x =17
Therefore: basketball = $17, football = $32

Let b = price of a basketball. Then the price of one football equals b + 15. Now, you can set up your equation to solve for b:

3b + 2(b + 15) = 115
3b + 2b + 30 = 115
5b = 85
b = 17

So, a basketball costs $17 and a football costs 17 + 15 = $32.

basketball= x
football= (x+15)

3x + 2(x+15) =115
5x + 30 = 115
5x = 85
x = 85/5
x =17
Therefore: basketball = $17, football = $32

So f = b + 15 and 3b+2f = 115.
3b+2(b+15) = 115
5b + 30= 115
b +6 = 23 of b = 17 and so f = 32.
B = price of basket ball and f= that of a football

The setup: Translate:

A football costs $15 more than a basketball: F = 15 + B
3 basketballs and 2 footballs cost at total of $115: 3B + 2F = 115

Now solve for F and B.