化簡以下各式,需列明步驟。
1.(a^2)^3*(a^4)^5÷(a^3)^4
2. (a^-2)^3÷(a^-3)^2
3.(ab)^6÷a^2b^4÷a^4b^2
4.(a^2/b)^3*(b^2/a)^2
5.(1/ab^-1)^-1
6. (-4a^2b^5)(-2abc^3)
7. -6xy分之-18x三次y+48x二次y二次-54xy三次+6x二次y
↑呢條煩d.所以表達方式吾同左-v-"
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2008-08-21 3:03 am
回答 (2)
2008-08-23 12:57 am
✔ 最佳答案
1.(a^2)^3*(a^4)^5÷(a^3)^4=a^6*a^20÷a^12
=a^(6+20-12)
=a^14
2. (a^-2)^3÷(a^-3)^2
=(a^-6)÷a^-6
=a(-6-(-6))
=0
3.(ab)^6÷a^2b^4÷a^4b^2
=a^(6-2-4)b^(6-4-2)
=0
4.(a^2/b)^3*(b^2/a)^2
=(a^6/b^3)*(b^4/a^2)
=a^(6-2)b(4-3)
=a^4b
5.(1/ab^-1)^-1
=(b/a)^-1
=a/b
6. (-4a^2b^5)(-2abc^3)
=-4(-2)a^(2+1)b^(5+1)c^3
=8a^3b^6c^3
7. I'm sorry... I'm not quite sure what are you talking about... sorry
2008-08-21 4:22 am
1.(a^2)^3*(a^4)^5÷(a^3)^4
= (a^6)(a^20)除以a^12
= a^(26-12)
= a^14
2. (a^-2)^3÷(a^-3)^2
= (a^-6)除以(a^-6)
= 0
= (a^6)(a^20)除以a^12
= a^(26-12)
= a^14
2. (a^-2)^3÷(a^-3)^2
= (a^-6)除以(a^-6)
= 0
收錄日期: 2021-04-15 17:53:15
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https://hk.answers.yahoo.com/question/index?qid=20080820000051KK02665