1) Solve for “x”: 32 = 8 – 4x
and then state the solution
27) Solve the system of equations and state the answer as an ordered pair.
y= 1/2x + 1
y= -2x+6
[[ ok for my answer i got that x = 2 ]]
but my teacher is asking me for y? and i dunno how 2 do that?
solve for x? plz? help?
2008-08-19 4:22 pm
回答 (10)
2008-08-19 4:27 pm
✔ 最佳答案
32 = 8 - 4x24 = -4x
x = -6
If you have your x, just substitute it into either of the two equations and solve for y:
y = (1/2)x + 1
y = (1/2)(2) + 1
y = 1 + 1
y = 2
or:
y = -2(2) + 6
y = -4 + 6
y = 2
Both gives the same answer.
2008-08-19 11:30 pm
1). 32 = 8 - 4x
4x = 8 - 32
x = -24/4
x = -6
2). use elimination
y=1/2x + 1
y= -2x + 6
------------------- (-)
0 = 1/2x+2x - 5
0 = 5/2x - 5
x = 5 times 2/5
x = 2
Ok...
4x = 8 - 32
x = -24/4
x = -6
2). use elimination
y=1/2x + 1
y= -2x + 6
------------------- (-)
0 = 1/2x+2x - 5
0 = 5/2x - 5
x = 5 times 2/5
x = 2
Ok...
2008-08-19 11:51 pm
1) 32 = 8 - 4x
Add 4x to both sides:
32 + 4x = 8
Subtract 32 from both sides:
4x = 8 - 32 = -24
4x = -24
Divide both sides by 4 to isolate the x
x = -6 <<<<<
2) I am going to do the entire problem from scratch.
(1) y = (1/2)x + 1
(2) y = -2x + 6
Multiply both sides of (1) by 4, so as to get the x term to be 2x.
(1a) 4y = 2x + 4
Add (1a) to (2) Repeating the equations
(1a) 4y = 2x + 4
(2) y = -2x + 6
---------------------
5y = 10
y = 2 <<<<<
Substitute 2 for y in equation (2)
2 = -2x + 6 Subtract 2 from both sides of the equation:
0 = -2x - 4
2x = 4
x = 2
(2,2) <<<<< Final Answer (This does check.)
Add 4x to both sides:
32 + 4x = 8
Subtract 32 from both sides:
4x = 8 - 32 = -24
4x = -24
Divide both sides by 4 to isolate the x
x = -6 <<<<<
2) I am going to do the entire problem from scratch.
(1) y = (1/2)x + 1
(2) y = -2x + 6
Multiply both sides of (1) by 4, so as to get the x term to be 2x.
(1a) 4y = 2x + 4
Add (1a) to (2) Repeating the equations
(1a) 4y = 2x + 4
(2) y = -2x + 6
---------------------
5y = 10
y = 2 <<<<<
Substitute 2 for y in equation (2)
2 = -2x + 6 Subtract 2 from both sides of the equation:
0 = -2x - 4
2x = 4
x = 2
(2,2) <<<<< Final Answer (This does check.)
2008-08-19 11:34 pm
1)
32 = 8 - 4x
32 - 8 = -4x
-4x = 24
x = 24/-4
x = -6
2)
y = 1/2x + 1 (solve by using substitution)
y = -2x + 6
y = 1/2x + 1
(-2x + 6) = 1/2x + 1
-2x - x/2 = -6 + 1
2(-2x - x/2) = 2(-5)
-4x - x = -10
-5x = -10
x = -10/-5
x = 2
y = -2x + 6
y = -2(2) + 6
y = -4 + 6
y = 2
â´ x = 2 , y = 2
32 = 8 - 4x
32 - 8 = -4x
-4x = 24
x = 24/-4
x = -6
2)
y = 1/2x + 1 (solve by using substitution)
y = -2x + 6
y = 1/2x + 1
(-2x + 6) = 1/2x + 1
-2x - x/2 = -6 + 1
2(-2x - x/2) = 2(-5)
-4x - x = -10
-5x = -10
x = -10/-5
x = 2
y = -2x + 6
y = -2(2) + 6
y = -4 + 6
y = 2
â´ x = 2 , y = 2
2008-08-19 11:32 pm
1 is -6. 4* -6= neg. 24. since the 8 is smaller than 32, the 4 has to become a negative #,and a negative being subtracted turns positive. so its really like saying 32=8+24. just put -6.
idk how u do 27.
idk how u do 27.
2008-08-19 11:31 pm
4y=2x+4
y=-2x+6
5y=10
y=2
2=x
y=-2x+6
5y=10
y=2
2=x
2008-08-19 11:30 pm
1) Get like terms on one side
32 -8 = 8 - 4x -8
24 = -4x
Divide both sides by -4 to get x by itself
-6 = x
27) You did the hard part by finding x=2. All you have to do now is plug in the x into one of equations to find the y since the coordinate for y is the same for both lines because we're trying to find the point that's the same.
So:
y = 1/2(2) + 1
y = 2
32 -8 = 8 - 4x -8
24 = -4x
Divide both sides by -4 to get x by itself
-6 = x
27) You did the hard part by finding x=2. All you have to do now is plug in the x into one of equations to find the y since the coordinate for y is the same for both lines because we're trying to find the point that's the same.
So:
y = 1/2(2) + 1
y = 2
2008-08-19 11:29 pm
1)
32 = 8 - 4x
24 = -4x
-6 = x
27)
If you believe x = 2 then all you have to do is plug 2 in for x in either equation and solve for y
I would recommend plugging x = 2 into both equations to ensure you get the same answer for both
32 = 8 - 4x
24 = -4x
-6 = x
27)
If you believe x = 2 then all you have to do is plug 2 in for x in either equation and solve for y
I would recommend plugging x = 2 into both equations to ensure you get the same answer for both
2008-08-19 11:29 pm
y=2 because when 1/2x =1 and x=2 then u plug it in then 1/2 times 2 equals 1 then 1+1 equals 2 then y=2. the same thing goes for the second problem -2 times 2 = -4... -4 + 6 = 2 then y=2...there is ur answer.... x=2 and y=2...
2008-08-19 11:28 pm
32 = 8 – 4x
Subtract 8 on both sides
24 = -4x
Divide by -4 on both sides
-6 = x
-----
y= 1/2x + 1
y= -2x+6
Both equations = y so you can set the equations to equal one another
1/2x + 1 = -2x + 6
1/2x + 2x = 6 - 1
5/2 x = 5
x = 5 * 2/5
x = 2
Then sub in 2 for x
y = 1/2 (2) + 1
y = 2
Subtract 8 on both sides
24 = -4x
Divide by -4 on both sides
-6 = x
-----
y= 1/2x + 1
y= -2x+6
Both equations = y so you can set the equations to equal one another
1/2x + 1 = -2x + 6
1/2x + 2x = 6 - 1
5/2 x = 5
x = 5 * 2/5
x = 2
Then sub in 2 for x
y = 1/2 (2) + 1
y = 2
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