Algeb need help on fraction values?

(3+x)/(8+x) = 2/3

9+3x = 16 +2x
3x - 2x = 16 - 9

x = 7

1/16

(3 + x)/(8 + x) = 2/3
3 + x = 2(8 + x)/3
3(3 + x) = 2*8 + 2*x
9 + 3x = 16 + 2x
-2x + 3x = 16 - 9
x = 7

2/3 - 3/8 = 16/24 - 9/24 = 7/24

3/8 + 7/24 = 2/3

4 added to numerator
16 added to deniminator.

Fraction ==> 3/8

Numerator = 3
Denominator = 8

Let X = number to be added

3 + X / 8 + X = 2/3

Cross multiplication

(3 + X) 3 = (8 + X) 2

9 + 3X = 16 + 2X

Transpose the variable to the left side and constant to the right side


3X - 2X = 16 - 9

X = 7

To check

3 + 7/ 8 + 7 = 10/15 = 2/3

add seven to each gives 10/15 = 2/3

You need to add 3 on numeratoro and 1 on denominator.

the answer is u must add 3 to Nr and 1 to DR.. u will get 6/9 which is equal to 2/3..

solution

let the fraction be x/y = 3/8

so x = 3y/8 ....eqn 1
and y = 3 / 8x
let p,q be the number to be added to Nr and Dr,

(x + p) / (y+q) = 2/3

on solving u get p = 3 and q = 1

i hope i helped..