solve for x. -6x+3x^2+1=0?

2008-08-18 6:58 pm
show all steps
and use the quadratic formula

回答 (3)

2008-08-18 7:36 pm
✔ 最佳答案
3x² - 6x + 1 = 0
x = [ 6 ± √ (36 - 12) ] / 6
x = [ 6 ± √ (24) ] / 6
x = [ 6 ± 2√6 ] / 6
x = 1 ± (1/3)√6
2008-08-18 7:05 pm
-6x + 3x^2 + 1 = 0
3x^2 - 6x + 1 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 3
b = -6
c = 1

x = [6 ±√(36 - 12)]/6
x = [6 ±√24]/6
x = [6 ±4.89]/6 (approx.)

x = [6 + 4.89]/6
x = 10.89/6
x = 1.815

x = [6 - 4.89]/6
x = 1.11/6
x = 0.185

∴ x ≈ 0.185 , 1.815
2008-08-18 7:03 pm
a=3
b=-6
c=1

Now put it into the formula!


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