Phy Time - Ans.fyi 參考答案

Phy Time

2008-08-19 3:30 am

1.The maximum error of the atomic caesium clocks installed at the Hong Kong Observatory is １０-6 per day.
a)What is its possible percentage error?
b)How long would it take to be in error by 1x.

2.John's watch runs slower that the actual time by one minute each day.John adjusted 1 January 2005.
a)What should the time be shown on John's watch when the actual time is 2:00 pm on 10 January 2005? Explain your answer briefy.
b)What is the percentage error of time shown on John's watch as compared with the correct time?

回答 (1)

天同

2008-08-20 5:49 am

✔ 最佳答案

1. There should be a unit to the error. I presume it is 10^-6 s per day.

(a) This percentage error = (10^-6/24x3600) x 100% = 1.157x10^-9 %

(b) Again, what does 1x mean?
I presume it is 1 s.

The time for an error of 1s occurs = 1/10^-6 days = 2738 years
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2. (a) The time from 1 January 2005 to 2:00pm on 10 January 2005
= 9 days 14 hours = 9.58333 days

John's watch should run behind by
= 9.58333 minutes
Hence, his watch should show 1:50:25 pm

(b) Percentage error = (9.58333/9.58333x60) x 100% = 1.67%

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